sinx=(x^2)/(625pi^2) - solution

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Solution for sinx=(x^2)/(625pi^2) equation:

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1/t-4 = 0

(3/2)*a^2*((4*a)/(b^2))*b^2 = 0

11.6/2 = 0

11/15 = (3/5)*p-((1/5)*p)

x/6-5 = x/3-7

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